48x^2-640x-2048=0

Solution for 48x^2-640x-2048=0 equation:

48x^2-640x-2048=0

a = 48; b = -640; c = -2048;
Δ = b2-4ac
Δ = -6402-4·48·(-2048)
Δ = 802816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{802816}=896$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-640)-896}{2*48}=\frac{-256}{96}
=-2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-640)+896}{2*48}=\frac{1536}{96}
=16
$